题目内容
如图,已知在△ABC中,点D、E分别在边AB和AC上,DE∥BC,
;(2)求作向量
(不要求写作法,但要指出所作图中表示结论的向量)。
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/201408230325598154451.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/201408230325597692330.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559784544.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/201408230325598154451.png)
(1)
=![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559847370.png)
+
;(2)取点AB的中点M,作
=
,连接
,则
即为所求.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559831420.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559847370.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559862296.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559878473.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559893455.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559909410.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559925527.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559925527.png)
试题分析:(1)由DE∥BC,AD:DB=2:3,根据平行线分线段成比例定理,可求得AE:AC=2:5,又由
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559971406.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559862296.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559909410.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032600018311.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032600018418.png)
(2)取点AB的中点M,作
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559893455.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559909410.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559925527.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559925527.png)
试题解析:(1)∵DE∥BC,
∴AE:AC=AD:AB="2:5" ,
∵
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559971406.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559862296.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559909410.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032600018311.png)
∴
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032600018418.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559971406.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559909410.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559862296.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032600018311.png)
∴
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559831420.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559847370.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032600018418.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559847370.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032600299431.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559847370.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559862296.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559878473.png)
(2)取点AB的中点M,作
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559893455.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559909410.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559925527.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823032559925527.png)
![](http://thumb.zyjl.cn/images/loading.gif)
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