题目内容
计算:(1)-24+3-16-5;
(2)-23÷
4 |
9 |
2 |
3 |
(3)
3 |
4 |
1 |
3 |
14 |
15 |
(4) (
1 |
2 |
1 |
3 |
5 |
6 |
9 |
14 |
5 |
9 |
(5)-14-(1-0.5)×
1 |
3 |
分析:根据有理数的混合运算顺序和运算律分别求出结果,即可求出答案.
解答:解:(1)-24+3-16-5
=-21-16-5
=-42
(2)-23÷
×(-
)2
=-8×
×
=-8
(3)
×(8-1
-
)
=
×8-
×
-
×
=6-1-
=4
(4) (
+
)÷(-
)-
×(-1
)
=
×(-
)-
×(-
)
=-1-(-1)
=0
(5)-14-(1-0.5)×
×[2-(-3)2]
=-1-
×
×(2-9)
=-1-(-
)
=
=-21-16-5
=-42
(2)-23÷
4 |
9 |
2 |
3 |
=-8×
9 |
4 |
4 |
9 |
=-8
(3)
3 |
4 |
1 |
3 |
14 |
15 |
=
3 |
4 |
3 |
4 |
4 |
3 |
3 |
4 |
14 |
15 |
=6-1-
7 |
10 |
=4
3 |
10 |
(4) (
1 |
2 |
1 |
3 |
5 |
6 |
9 |
14 |
5 |
9 |
=
5 |
6 |
6 |
5 |
9 |
14 |
14 |
9 |
=-1-(-1)
=0
(5)-14-(1-0.5)×
1 |
3 |
=-1-
1 |
2 |
1 |
3 |
=-1-(-
7 |
6 |
=
1 |
6 |
点评:本题主要考查了有理数的混合运算,在解题时要注意运算顺序和运算律的综合应用.
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