题目内容
如图6,在等腰直角三角形ABC中,∠C=90°,点D为AB的中点,已知扇形EAD和扇形FBD的圆心分别为点A、点B,且AC=2,则图中阴影部分的面积为_________(结果不去近似值).


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分析:用三角形ABC的面积减去扇形EAD和扇形FBD的面积,即可得出阴影部分的面积.
解答:解:∵BC=AC,∠C=90°,AC=2,
∴AB=2
,
∵点D为AB的中点,
∴AD=BD=
∴S阴影=S△ABC-S扇形EAD-S扇形FBD
=
×2×2-
×2,
=2-
故答案为:2-
.
解答:解:∵BC=AC,∠C=90°,AC=2,
∴AB=2

∵点D为AB的中点,
∴AD=BD=

∴S阴影=S△ABC-S扇形EAD-S扇形FBD
=


=2-
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