题目内容
(1)计算(
+
)(
-2);
(2)
•(-
)÷
(a>0,b>0)
3 |
2 |
6 |
(2)
8a3b2 |
3 |
2 |
2a2b |
9ab |
(1)原式=
×
-2
+
×
-2
=3
-2
+2
-2
=
;
(2)原式=2ab
•(-
a
)÷3
=2ab•(-
a)•
=-2a2b.
3 |
6 |
3 |
2 |
6 |
2 |
2 |
3 |
3 |
2 |
2 |
(2)原式=2ab
2a |
3 |
2 |
2b |
ab |
3 |
2 |
1 |
3 |
|
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