题目内容
如图,△ABC的面积是12,BD=2CD,点E是AD的中点,则△ACE的面积是______.
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∵BD=2CD,
∴S△ABD=2S△ADC,
∵△ABC的面积是12,
∴S△ABD=
×12=8,S△ADC=
×12=4,
∵点E是AD的中点,
∴S△AEC=S△CED=
S△ADC=2.
故答案为:2.
∴S△ABD=2S△ADC,
∵△ABC的面积是12,
∴S△ABD=
2 |
3 |
1 |
3 |
∵点E是AD的中点,
∴S△AEC=S△CED=
1 |
2 |
故答案为:2.
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