题目内容

(10分) 如图,Rt△ABC中,∠C = 90°,把Rt△ABC绕着B点逆时针旋转,得到Rt△DBE,点EAB上.

(1)若∠BDA = 70°,求∠BAC的度数.
(2)若BC = 8,AC = 6,求△ABDAD边上的高.

(1)∠BAC =
(2)

解:(1) 由旋转得△ACB≌△DEB
BD = BA
∴∠BAD =BDA =
∴∠ABD =
∴∠ABC =ABD =
∵∠C =
∴∠BAC =·········································································· 5分
(2) ∵BC = 8,AC = 6,∠C =

∵∠DEB =C =BE = BC = 8,DE ="AC" = 6
AE =" AB" – BE = 2
在Rt△DEA中,
AD边上的高为h

······················································· 10分
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