题目内容
如图,P是平行四边形ABCD内一点,且S△PAB=5,S△PAD=2,则阴影部分的面积为______.


∵S△PAB+S△PCD=
S?ABCD=S△ACD,
∴S△ACD-S△PCD=S△PAB,
则S△PAC=S△ACD-S△PCD-S△PAD,
=S△PAB-S△PAD,
=5-2,
=3.
故答案为:3.
1 |
2 |
∴S△ACD-S△PCD=S△PAB,
则S△PAC=S△ACD-S△PCD-S△PAD,
=S△PAB-S△PAD,
=5-2,
=3.
故答案为:3.

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