题目内容
在正实数范围内,只存在一个数是关于的方程的解,求实数的取值范围.
或或.解析:
原方程可化为,①········································ (1分)
(1)当△=0时,,满足条件;·································· (2分)
(2)若是方程①的根,得,.此时方程①的另一个根为,故原方程也只有一根.·························································································· (4分)
(3)当方程①有异号实根时,,得,此时原方程也只有一个正实数根; (6分)
(4)当方程①有一个根为0时,,另一个根为,此时原方程也只有一个正实根。 (8分)
综上所述,满足条件的的取值范围是或或.
原方程可化为,①········································ (1分)
(1)当△=0时,,满足条件;·································· (2分)
(2)若是方程①的根,得,.此时方程①的另一个根为,故原方程也只有一根.·························································································· (4分)
(3)当方程①有异号实根时,,得,此时原方程也只有一个正实数根; (6分)
(4)当方程①有一个根为0时,,另一个根为,此时原方程也只有一个正实根。 (8分)
综上所述,满足条件的的取值范围是或或.
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