ÌâÄ¿ÄÚÈÝ

(9·Ö)21ÊÀ¼ÍÊǺ£Ñ󿪷¢ÓëÀûÓõÄÊÀ¼Í¡£ÑĮ̀µÄ¡°Ê®¶þÎ塱¹æ»®È·Á¢ÁË¡°À¶É«¾­¼Ã¡±·¢Õ¹Õ½ÂÔ£¬º£Ñó»¯Ñ§×ÊÔ´µÄ×ÛºÏÀûÓý«ÊÇÖص㷢չÁìÓòÖ®Ò»¡£
(1)º£Ë®µ­»¯£ºÕôÁ󷨵­»¯º£Ë®ÊÇÀûÓú£Ë®Öи÷³É·ÝµÄ            ²»Í¬·ÖÀë³öµ­Ë®£»¸ßѹ·´Éø͸Ĥ·¨µ­»¯º£Ë®ÊÇÀûÓú£Ë®Öи÷³É·ÝµÄ              ²»Í¬·ÖÀë³öµ­Ë®¡£
(2)ÖÆÑΣº¢ÙÖÆ´ÖÑΡ£´Ó±ˮÖÐÌáÈ¡´ÖÑÎÓõĽᾧ·½·¨ÊÇ              ¡£¢Ú´ÖÑδ¿»¯¡£´ÖÑÎÖк¬ÓÐÄàɳ¡¢ÁòËáþ¡¢ÂÈ»¯¸ÆµÈÔÓÖÊ¡£½«´ÖÑÎÈÜÓÚË®£¬È»ºóͨ¹ýÈçϲÙ×÷¼´¿ÉµÃµ½½Ï´¿µÄÂÈ»¯ÄÆ£ºa¹ýÂË£®b¼Ó¹ýÁ¿µÄBa(OH)2ÈÜÒº£»c¼ÓÊÊÁ¿µÄÑÎË᣻d¼Ó¹ýÁ¿µÄNa2CO3ÈÜÒº£»eÕô·¢¡£ÕýÈ·µÄ²Ù×÷˳ÐòÊÇ               (Ìî×Öĸ)¡£
(3)ÖƼ°±¼î·¨ÖÆ´¿¼îµÄÁ÷³ÌͼÈçÏ£º

Íê³ÉͼÖС°(   )¡±µÄÄÚÈÝ£º¢Ù           £»¢Ú           £»¢Û           ¡£
(4)ÖÆþ£º¹¤ÒµÉÏÒ»°ãÓõç½âÈÛÈÚ״̬µÄÂÈ»¯Ã¾ÖƽðÊôþ£¬ÈôÒÔ±ˮ(º¬ÓÐÁòËáþ¡¢ÂÈ»¯ÄƺÍÂÈ»¯¸Æ)ΪÆðʼԭÁÏÀ´ÖÆÈ¡½ðÊôþ£¬Çë»­³öÖÆþµÄÁ÷³Ìͼ¡£
(9·Ö)(1)·Ðµã   ¿ÅÁ£´óС    (2)Õô·¢½á¾§    bdace(¹ýÂË¿ÉÖظ´Ê¹ÓÃ)
(3)¢ÙNH3   ¢ÚCO2   ¢Û¼ÓÈÈ(»òÈȽâ)
£¨4£©£¨2·Ö£¬Ð´³öÖмäÁ½²½¼´¸ø·Ö£©
·ÖÎö£º£¨1£©º£Ë®µ­»¯µÄ·½·¨Ö÷ÒªÓУºÕôÁ󷨡¢½á¾§·¨¡¢µ­»¯Ä¤·¨¡¢¶à¼¶ÉÁ¼±ÕôÁ󷨣¬¿É¸ù¾ÝÔ­Àí½øÐзÖÎö£®
£¨2£©¢Ù¿É¸ù¾ÝÂÈ»¯ÄÆÈܽâ¶ÈÓëζȵĹØϵ½øÐзÖÎöÑ¡Ôñ½á¾§·½·¨£®
¢Ú¸ù¾Ý³ýÔÓʱ²»ÒýÈëÐÂÔÓÖʵÄÔ­Àí¼°ÊµÑéÄ¿µÄ½øÐзÖÎö£®
£¨3£©¸ù¾ÝÎïÖʵĻ¯Ñ§ÐÔÖʽøÐÐÑ¡ÔñÊÔ¼Á£®
£¨4£©¿É¸ù¾ÝÆðʼÎïÖʺÍ×îÖÕÎïÖʽøÐÐÕýÄæÍƵ¼£®
½â£º£¨1£©ÕôÁ󷨵­»¯º£Ë®ÊÇÀûÓú£Ë®Öи÷³É·ÝµÄ·Ðµã±È½Ï¸ß£¬Ë®µÄ·Ðµã±È½ÏµÍ½øÐзÖÀëµÄ£»¸ßѹ·´Éø͸Ĥ·¨µ­»¯º£Ë®ÊÇÀûÓú£Ë®Öи÷³É·ÝµÄ¿ÅÁ£´óС²»Í¬£¬Ë®·Ö×Ó¿ÉÒÔͨ¹ýµ­»¯Ä¤£¬ÆäËüÀë×Ó²»»áͨ¹ý£®
¹Ê´ð°¸Îª£º·Ðµã£» ¿ÅÁ£´óС
£¨2£©ÒòΪÂÈ»¯ÄƵÄÈܽâ¶ÈËæζȵı仯²»´ó£¬ËùÒÔ²ÉÓÃÕô·¢ÈܼÁ·¨½á¾§£»
Òª³ýÈ¥´ÖÑÎÖк¬ÓеÄÔÓÖÊ£¬¿ÉÒÔ¼Ó¹ýÁ¿µÄÇâÑõ»¯±µÈÜÒº³ýÈ¥ÁòËáþ£¬¼Ó¹ýÁ¿µÄNa2CO3ÈÜÒº³ýÈ¥ÂÈ»¯¸ÆºÍ¹ýÁ¿ÊÔ¼ÁÇâÑõ»¯±µ£¬Í¨¹ý¹ýÂ˰Ѳ»ÈÜÓÚË®µÄÎïÖʳýÈ¥£¬¼ÓÊÊÁ¿µÄÑÎËá³ýÈ¥¹ýÁ¿µÄ̼ËáÄÆ£¬Í¨¹ýÕô·¢³ýÈ¥ÑÎËᣮ
¹Ê´ð°¸Îª£ºÕô·¢½á¾§£»bdace
£¨3£©¸ù¾ÝÌâÖÐËù¸øÉú³ÉÎï½øÐзÖÎö£¬ÒªÖƱ¸±¥ºÍ°±Ë®¿Ï¶¨Êǽ«°±Ë®Í¨ÈëʳÑÎË®ÖУ¬Óɱ¥ºÍµÄ°±Ë®Ê³ÑÎÈÜÒºÖƱ¸Ì¼ËáÇâÄÆ£¬¸ù¾ÝÎïÖʵÄÐÔÖʺÍÔªËØÊغã֪ӦͨÈë¶þÑõ»¯Ì¼ÆøÌ壻̼ËáÇâÄÆÊÜÈÈÒ×·Ö½â±äΪ̼ËáÄÆ£®
¹Ê´ð°¸Îª£º¢ÙNH3 ¢ÚCO2 ¢Û¼ÓÈÈ
£¨4£©Ê×ÏȱØÐ뽫±ˮÖÐþ½øÐи»¼¯£¬¼ÓÈëʯ»ÒÈ飨±È½Ï¾­¼Ã£¬²»ÄÜÓÃÇâÑõ»¯ÄÆ£©£¬±äΪÇâÑõ»¯Ã¾³Áµí£¬¹ýÂ˺ó¼ÓÈëÑÎËáÖƱ¸ÂÈ»¯Ã¾£¬ÔÙ¾­¹ýÕô·¢¸ÉÔïÖƱ¸ÎÞË®ÂÈ»¯Ã¾£¬×îºó¾­¹ýͨµç¿ÉÖƵÃþ£®
¹Ê´ð°¸Îª£º
µãÆÀ£º±¾ÌâÄѶȱȽϴó£¬Éæ¼°º£Ë®µ­»¯·½·¨µÄÔ­Àí¡¢º£Ë®É¹ÑεÄÔ­Àí¡¢³ýÔÓµÄÔ­Àí¡¢ºîÊÏÖƼµÄÔ­ÀíµÈÀíÂÛÄÚÈÝ£¬ÒªÍ¨¹ý¸ÃÌâÈÏÕæ×ܽᣮ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨10£¬Â¦µ×29£©Ð¡ÁÖ¾õµÃÄãºÜ´ÏÃ÷£¬ÊÇËûµÄÁ¼Ê¦ÒæÓÑ£¬Ñ§Íê¡°ËáµÄ»¯Ñ§ÐÔÖÊ¡±ºó£¬ÑûÇëÄãÓëËûÌÖÂÛ¡°Ê³´×ÔÚ³ø·¿ÖеÄÃîÓá±£º
£¨1£©¸´Ï°ËáµÄ»¯Ñ§ÐÔÖÊ
¢ÙËáÓëָʾ¼Á×÷ÓÃ
ËáÈÜÒºÄÜʹ×ÏɫʯÈïÈÜÒº±äºìÉ«
ËáÈÜÒº²»ÄÜʹÎÞÉ«·Ó̪ÈÜÒº±äÉ«
¢ÚËáÓë»îÆýðÊô×÷ÓÃ
Fe+2HCl=FeCl2+H2¡ü
Fe+H2SO4=FeSO4+H2¡ü
¢ÛËáÓëijЩ½ðÊôÑõ»¯Îï×÷ÓÃ
Fe2O3+HCl=FeCl3+H2O
¡­¡­
¢Ü¡­¡­
 
 
ÓÉÓÚСÁֵĿÎÌñʼÇû×öºÃ£¬¡°¢ÛËáÓëijЩ½ðÊôÑõ»¯Îï×÷ÓᱺóÃæµÄ»¯Ñ§·½³ÌʽδÅäƽ£¬Çë°ïËûд³öÅäƽºóµÄ»¯Ñ§·½³Ìʽ£º                    63                  ¡£
£¨2£©ÌÖÂÛ½»Á÷
¢Ù СÁÖ×ÔºÀµØ˵£¬Ä¿Ç°ÊÀ½çÎÀÉú×éÖ¯ÕýÔÚÍƹãʹÓÃÖйúÌú¹ø£¬Ê¹ÓÃÌú¹ø³´²Ëʱ£¬·Åµãʳ´×ʱ£¬¿ÉÒÔ²¹³äÈËÌåÐèÒªµÄ΢Á¿ÔªËØ          64       ÔªËØ£¬¸Ã·´Ó¦µÄÔ­ÀíÊÇÀûÓÃÁËËáµÄ»¯Ñ§ÐÔÖÊ         65       £¨ÌîÐòºÅ¡°¢Ù¡±¡¢¡°¢Ú¡±»ò¡°¢Û¡±£©¡£
¢Ú Äã¸æËßСÁÖ£¬Ê³´×µÄ×÷ÓÃÔ¶Ô¶²»Ö¹ÕâЩÄØ£¬Èç     66    £¨ÈÎдһµãʳ´×ÔÚÉú»îÖеÄÃîÓã©¡£
£¨3£©·´Ë¼
ÑÎËá¡¢ÁòËᡢʳ´×¾ßÓÐÏàËÆ»¯Ñ§ÐÔÖʵÄÔ­ÒòÊÇÒòΪËüÃǵÄË®ÈÜÒºÖж¼º¬ÓР 67 Àë×Ó¡£
(7·Ö)¡°Å£ÈâÃ桱ÊÇÀ¼ÖݵķçζС³ÔÖ®Ò»£¬ÆäÖƹý³ÌÖмÓÈëÁËÒ»ÖÖ½Ð×ö¡°Åî»Ò¡±µÄºÍÃæ¼Á¡£¡°Åî»Ò¡±ÊÇÅî²ÝÉÕÖƶø³ÉµÄ»Ò¡£Ä³Ð£»¯Ñ§ÐËȤС×éµÄͬѧ¶Ô¡°Åî»Ò¡±µÄ»¯Ñ§³É·Ö¼°»¯Ñ§ÐÔÖʺܸÐÐËȤ£¬ÓÚÊǽøÐÐÁËһЩʵÑé̽¾¿¡£ÇëÄã°ïËûÃÇÌî³äÏÂÁÐʵÑé¹ý³ÌµÄ±í¸ñ¡£
¡¾²éÔÄ×ÊÁÏ¡¿º¬ÓмØÔªËصĻ¯ºÏÎ×ÆÉÕʱ»ðÑæ³Ê×ÏÉ«¡£
¡¾ÊµÑé¹ý³Ì¡¿
   ÊµÑé²½ÖèÓë·½·¨
   ÊµÑéÏÖÏó
   ÊµÑé½áÂÛ
£¨1£©²âpH£ºÈ¡ÉÙÁ¿¡°Åî»Ò¡°ÑùÆ·ÓÚÊÔ¹ÜÖУ¬¼ÓÈëÊÊÁ¿µÄË®Èܽ⣬                      
                                
                                
 
pH>7
 
                    
                     
(2)×ÆÉÕ£ºÓò¬Ë¿ÕºÈ¡ÉÙÁ¿¡°Åî»Ò¡±ÈÜ
Òº²¢×ÆÉÕ
   »ðÑæ³Ê×ÏÉ«
 
                     
(3)¼ìÑéC032-£ºÈ¡ÉÙÁ¿¡°Åî»Ò¡±¹ÌÌåÓÚ
ÊÔ¹ÜÖУ¬ÏòÆäÖеμӠ             £¬
½«Éú³ÉµÄÆøÌåͨÈ˳ÎÇåµÄʯ»ÒË®
                            
                            
 
¡°Åî»Ò¡±Öк¬ÓÐC032-
С×éͬѧÌÖÂÛºóÒ»ÖÂÈÏΪ¡°Åî»Ò¡±µÄÖ÷Òª³É·ÖÊÇ̼Ëá¼Ø¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø