ÌâÄ¿ÄÚÈÝ

С¸ÕÔÚ»¯Ñ§ÊµÑéÊÒ·¢ÏÖ£¬Ê¢·ÅÉÕ¼î¹ÌÌåµÄÊÔ¼ÁÆ¿Æ¿¿Úδ¸Ç¶ÖÃÔÚ¿ÕÆøÖУ®Ð¡¸Õ½ÐÀ´Ð¡¾üºÍСºì£¬¹²Í¬Ì½¾¿ÕâÖÖÉÕ¼îµÄÊÇ·ñ±äÖÊ£®Îª²â¶¨Æä³É·Ö£¬Ð¡Ã÷³ÆÈ¡¸ÃÉÕ¼îÑùÆ·3g£¬³ä·ÖÈܽâÓÚË®ÖУ¬ÔٵμÓÇâÑõ»¯¸ÆÈÜÒº£¬²úÉú³ÁµíµÄÖÊÁ¿Óë¼ÓÈëÇâÑõ»¯¸ÆÈÜÒºµÄÖÊÁ¿¹ØϵÈçÓÒͼËùʾ£®Çó£º
£¨1£©²úÉúµÄ³ÁµíÊÇ______£¨Ìѧʽ£©£»
£¨2£©¸ÃÉÕ¼îÑùÆ·ÖÐÇâÑõ»¯ÄƵÄÖÊÁ¿£»£¨±£ÁôСÊýºóÁ½Î»£©
£¨3£©Ëù¼ÓÈëÇâÑõ»¯¸ÆÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£®
£¨1£©ÇâÑõ»¯¸ÆºÍ̼ËáÄÆÉú³É̼Ëá¸ÆºÍÇâÑõ»¯ÄÆ£¬Ì¼Ëá¸ÆÊdzÁµí£¬¹Ê´ð°¸Îª£ºCaCO3£®
£¨2£©´ÓͼÏó¿ÉÒÔ¿´³ö£¬µ±ÇâÑõ»¯ÄÆÈÜÒºµÄÖÊÁ¿´ïµ½200¿Ë£¬³ÁµíÖÊÁ¿Ò²´ïµ½×î´óÖµ£¨0.3¿Ë£©£®ÉèÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿ÊÇX£¬²Î¼Ó·´Ó¦µÄÇâÑõ»¯¸ÆµÄÖÊÁ¿ÊÇY£®
Ca£¨OH£©2+Na2CO3¨TCaCO3¡ý+2NaOH
74 106 100
Y X 0.3¿Ë
74
100
¨T
Y
0.3¿Ë

µÃ£ºY=0.22¿Ë
106
100
¨T
X
0.3¿Ë

µÃ£ºX=0.32¿Ë
¡àÉÕ¼îÑùÆ·ÖÐÇâÑõ»¯ÄƵÄÖÊÁ¿=3¿Ë-0.32¿Ë=2.68¿Ë£®
£¨3£©ÓÉ£¨2£©¼ÆËã³öÇâÑõ»¯¸ÆµÄÖÊÁ¿ÊÇ0.22¿Ë£®´ÓͼÏó¿ÉÒÔ¿´³ö£¬ÇâÑõ»¯¸ÆÈÜÒºµÄÖÊÁ¿ÊÇ200¿Ë£¬ËùÒÔÇâÑõ»¯¸ÆÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý=
0.22¿Ë
200¿Ë
¡Á100%¨T0.11%£®
´ð£º¸ÃÉÕ¼îÑùÆ·ÖÐÇâÑõ»¯ÄƵÄÖÊÁ¿Îª2.68¿Ë£»Ëù¼ÓÈëÇâÑõ»¯¸ÆÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ0.11%£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø