ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿»¯Ñ§¾ÍÔÚÎÒÃÇÉí±ß£¬Éú»îºÍÉú²úÖÐÔ̲Ø×ŷḻµÄ»¯Ñ§ÖªÊ¶¡£
(1)ÓÃÏ´µÓ¼ÁÇåÏ´ÓÍÎÛ£¬ÊÇÀûÓÃÁËÏ´µÓ¼ÁµÄ_______×÷Óá£
(2)ÈËÌåÌúÔªËØÉãÈëÁ¿¹ýÉÙ»áÒýÆð_______£¬ÓÃÌú¹ø³´²Ë¿É²¹³äÈËÌåËùÐèµÄÌúÔªËØ£¬µ«Ìú¹øÒ×ÉúÐâÊÇÒòΪÌúºÍ_______½Ó´¥¡£
(3)ΪÁ˼ìÑéºÓË®ÊÇÈíË®»¹ÊÇӲˮ£¬¿ÉÏòË®ÑùÖмÓÈë______£¬½Á°è£»ÈôË®Ñù»ë×Ç£¬¿ÉÏòË®ÑùÖмÓÈëÃ÷·¯½Á°èÈܽ⣬¾²ÖÃÒ»¶Îʱ¼äºó¹ýÂË£¬¹ýÂ˲Ù×÷ÖбØÐëҪʹÓõIJ£Á§ÒÇÆ÷ÓÐÉÕ±¡¢Â©¶·»¹ÓÐÒ»ÖÖÒÇÆ÷£¬¸ÃÒÇÆ÷µÄ×÷ÓÃÊÇ_____¡£
(4)ÌìÈ»ÆøÊdz£¼ûµÄȼÁÏ£¬Çëд³öÌìÈ»ÆøȼÉյĻ¯Ñ§·½³Ìʽ£º_____¡£
¡¾´ð°¸¡¿È黯 ƶѪ²¡ ÑõÆø¡¢Ë® ·ÊÔíË® ÒýÁ÷ CH4 + 2O2CO2 + 2H2O
¡¾½âÎö¡¿
(1)ÓÃÏ´µÓ¼ÁÇåÏ´ÓÍÎÛ£¬ÊÇÀûÓÃÁËÏ´µÓ¼ÁµÄÈ黯×÷Óã¬ÔÚ±íÃæ»îÐÔ¼ÁµÄ×÷ÓÃÏ·ÖÉ¢³ÉСҺµÎ¶ø±»³åÏ´µô£»
(2)ÈËÌåÌúÔªËØÉãÈëÁ¿¹ýÉÙ»áÒýÆðƶѪ²¡£¬ÓÃÌú¹ø³´²Ë¿É²¹³äÈËÌåËùÐèµÄÌúÔªËØ£¬µ«Ìú¹øÒ×ÉúÐâÊÇÒòΪÌúºÍÑõÆø¡¢Ë®½Ó´¥£»
(3)ΪÁ˼ìÑéºÓË®ÊÇÈíË®»¹ÊÇӲˮ£¬¿ÉÏòË®ÑùÖмÓÈë·ÊÔíË®£¬½Á°è£¬ÅÝĶมÔüÉÙΪÈíË®£¬·´Ö®ÎªÓ²Ë®£»ÈôË®Ñù»ë×Ç£¬¿ÉÏòË®ÑùÖмÓÈëÃ÷·¯½Á°èÈܽ⣬¾²ÖÃÒ»¶Îʱ¼äºó¹ýÂË£¬¹ýÂ˲Ù×÷ÖбØÐëҪʹÓõIJ£Á§ÒÇÆ÷ÓÐÉÕ±¡¢Â©¶·£¬»¹ÓÐÒ»ÖÖÒÇÆ÷ÊDz£Á§°ô£¬¸ÃÒÇÆ÷µÄ×÷ÓÃÊÇÒýÁ÷£¬·ÀÖ¹×ÇÒºÈ÷ÔÚ¹ýÂËÆ÷Íâ±ß»ò³å»µÂËÖ½£»
(4)ÌìÈ»ÆøÊdz£¼ûµÄȼÁÏ£¬ÌìÈ»ÆøµÄÖ÷Òª³É·ÖÊǼ×Í飬ȼÉյĻ¯Ñ§·½³Ìʽ£ºCH4 + 2O2CO2 + 2H2O¡£
¡¾ÌâÄ¿¡¿¶ÔÏÂÁÐʵÑéÖ¸¶¨ÈÝÆ÷ÖеÄË®£¬Æä½âÊÍûÓÐÌåÏÖË®µÄÖ÷Òª×÷ÓõÄÊÇ£¨¡¡¡¡£©
A | B | C | D | |
ʵÑé×°Öà | ÁòÔÚÑõÆøÖÐȼÉÕ | ²â¶¨¿ÕÆøÖÐÑõÆøº¬Á¿ | ÌúË¿ÔÚÑõÆøÖÐȼÉÕ | ÅÅË®·¨ÊÕ¼¯ÇâÆø |
½âÊÍ | ¼¯ÆøÆ¿ÖеÄË®£ºÎüÊշųöµÄÈÈ | Á¿¼òÖеÄË®£ºÍ¨¹ýË®Ìå»ýµÄ±ä»¯µÃ³öO2Ìå»ý | ¼¯ÆøÆ¿ÖеÄË®£ºÀäÈ´½¦ÂäÈÚÈÛÎ·ÀÖ¹¼¯ÆøÆ¿Õ¨ÁÑ | ¼¯ÆøÆ¿ÖеÄË®£ºÏȽ«¼¯ÆøÆ¿ÄڵĿÕÆøÅž»£¬ºó±ãÓÚ¹Û²ìH2ºÎʱÊÕ¼¯Âú |
A.AB.BC.CD.D