ÌâÄ¿ÄÚÈÝ
°ÑMgCl2¡¢AlCl3Á½ÖÖ¹ÌÌå×é³ÉµÄ»ìºÏÎïÈÜÓÚ×ãÁ¿µÄË®ºó£¬ÔÚËùµÃÈÜÒºÖÐÖðµÎ¼ÓÈë10%µÄNaOHÈÜÒº£¬¼ÓÈëNaOHÈÜÒºµÄÖÊÁ¿ºÍÉú³É³ÁµíµÄÖÊÁ¿ÈçÏÂͼËùʾ¡£ÒÑÖª£ºNaOHÓëAlCl3·´Ó¦Ê±£¬ÏÈʹAlCl3È«²¿×ª»¯Îª²»ÈÜÓÚË®µÄAl(OH)3£¬È»ºóAl(OH)3»¹ÄܼÌÐøÓë¹ýÁ¿µÄNaOH·¢ÉúÈçÏ·´Ó¦£ºAl(OH)3+NaOH====NaAlO2+2H2O£¬ÆäÖÐNaAlO2 ÊÇ¿ÉÈÜÓÚË®µÄÎïÖÊ£¬ÊԻشð£º
£¨1£©AµãµÄ³ÁµíÎïµÄ»¯Ñ§Ê½ÓÐ £» BµãµÄ³ÁµíÎïµÄ»¯Ñ§Ê½ÊÇ £»
£¨2£©Ô»ìºÏÎïÖÐMgCl2¡¢AlCl3µÄÖÊÁ¿¸÷Ϊ¶àÉÙ¿Ë£¿
£¨2£©Ô»ìºÏÎïÖÐMgCl2¡¢AlCl3µÄÖÊÁ¿¸÷Ϊ¶àÉÙ¿Ë£¿
½â£º
£¨1£©Mg(OH)2¡¢Al(OH)3£» Mg(OH)2
£¨2£©Al(OH)3 + NaOH = NaAlO2 + 2H2O
78 40
x 40g¡Á10%
x = 7.8g
AlCl3 + 3NaOH = Al(OH)3¡ý+ 3NaCl
133.5 78
y 7.8g
y = 13.35g
MgCl2 + 2NaOH = Mg(OH)2¡ý + 2NaCl
95 58
z 13.6g-7.8g
z = 9.5g
´ð£ºAlCl3Ϊ13.35g£¬MgCl2Ϊ9.5g
£¨1£©Mg(OH)2¡¢Al(OH)3£» Mg(OH)2
£¨2£©Al(OH)3 + NaOH = NaAlO2 + 2H2O
78 40
x 40g¡Á10%
x = 7.8g
AlCl3 + 3NaOH = Al(OH)3¡ý+ 3NaCl
133.5 78
y 7.8g
y = 13.35g
MgCl2 + 2NaOH = Mg(OH)2¡ý + 2NaCl
95 58
z 13.6g-7.8g
z = 9.5g
´ð£ºAlCl3Ϊ13.35g£¬MgCl2Ϊ9.5g
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿