ÌâÄ¿ÄÚÈÝ

ÔÚÒ»ÃܱÕÈÝÆ÷ÄÚÓÐÑõÆø¡¢¶þÑõ»¯Ì¼¡¢Ë®ÕôÆø¼°Ò»ÖÖδ֪ÎïM£¬ÔÚÒ»¶¨Ìõ¼þϳä·Ö·´Ó¦£¬²âµÃ·´Ó¦Ç°ºó¸÷ÎïÖʵÄÖÊÁ¿ÈçÏ£º
¡¡¡¡ÎïÖÊ ÑõÆø ¶þÑõ»¯Ì¼ Ë®ÕôÆø M
·´Ó¦Ç°ÖÊÁ¿/g 100 1 1 46
·´Ó¦ºóÖÊÁ¿/g 4 89 55 x
£¨1£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬ÄãÈÏΪXµÄֵӦΪ
 
£®
£¨2£©Î´ÖªÎïMÖÐÒ»¶¨º¬ÓеÄÔªËØΪ£¨ÌîÔªËØ·ûºÅ£©
 
£®
£¨3£©ÒÑ֪δ֪ÎïMµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª46£¬ÍƳöÆ仯ѧʽΪ
 
£®
£¨4£©¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
 
£®
·ÖÎö£º£¨1£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬ÓÉÎïÖÊÖÊÁ¿µÄÔö¼õÁ¿¿ÉÈ·¶¨·´Ó¦ÎïºÍÉú³ÉÎïµÄÖÊÁ¿£¬´Ó¶øµÃ³öXµÄÖµ£»
£¨2£©¸ù¾ÝÎïÖʵĻ¯Ñ§Ê½ºÍÎïÖʵÄÖÊÁ¿¿ÉÈ·¶¨ÎïÖʵÄÔªËØ×é³É£»
£¨3£©¸ù¾ÝÎïÖÊÖÐÔªËصÄÖÊÁ¿¿ÉÈ·¶¨¹¹³ÉÎïÖʵÄÔ­×Ó¸öÊý±È£¬´Ó¶øµÃµ½ÎïÖʵĻ¯Ñ§Ê½£»
£¨4£©¸ù¾Ý»¯Ñ§·½³ÌʽµÄÊéд²½Öè¿Éд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£®
½â´ð£º½â£º¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬ÓɱíÖÐÊý¾Ý¿ÉÖª£º
¶þÑõ»¯Ì¼µÄÖÊÁ¿Ôö¼ÓÁË89g-1g=88g£¬¿ÉÈ·¶¨¶þÑõ»¯Ì¼ÊÇÉú³ÉÎ
Ë®ÕôÆøµÄÖÊÁ¿Ôö¼ÓÁË55g-1g=54g£¬¿ÉÈ·¶¨Ë®ÕôÆøÊÇÉú³ÉÎ
ÑõÆøµÄÖÊÁ¿¼õÉÙÁË100g-4g=96g£¼88g+54g£¬¿ÉÈ·¶¨ÑõÆøºÍM¶¼ÊÇ·´Ó¦Î
£¨1£©M¼õÉÙµÄÖÊÁ¿Îª£º88g+54g-96g=46g£¬Òò´ËXµÄֵΪ£º46-46=0£®
£¨2£©Òò·´Ó¦ÎïÖеÄÑõÆøÀïÖ»º¬ÑõÔªËØ£¬Òò´ËÉú³ÉÎïÖеÄ̼ԪËغÍÇâÔªËØÒ»¶¨À´×ÔM£¬¼´MÖÐÒ»¶¨º¬ÓÐ̼¡¢ÇâÁ½ÔªËØ£»
Éú³ÉÎïÖÐÑõÔªËصÄÖÊÁ¿Îª88g¡Á
16¡Á2
44
+54g¡Á
16
18
=112g£¾96g£¬¿ÉÈ·¶¨Éú³ÉÎïÖеÄÒ»²¿·ÖÑõÔªËØÀ´×ÔM£¬¼´MÖÐÒ»¶¨º¬ÓÐÑõÔªËØ£®
£¨3£©MÖÐ̼¡¢Çâ¡¢ÑõÈýÔªËصÄÔ­×Ó¸öÊý±ÈΪ
88g¡Á
12
44
12
£º
54g¡Á
1¡Á2
18
1
£º
112g-96g
16
=2£º6£º1£¬¹ÊMµÄ»¯Ñ§Ê½ÎªC2H6O£»
£¨4£©¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪC2H6O+3O2
 µãȼ 
.
 
2CO2+3H2O£®
¹Ê´ð°¸Îª£º£¨1£©O£»£¨2£©C¡¢H¡¢O£»£¨3£©C2H6O£»£¨4£©C2H6O+3O2
 µãȼ 
.
 
2CO2+3H2O£®
µãÆÀ£º±¾Ì⿼²éÁËÖÊÁ¿Êغ㶨ÂÉ¡¢ÓйØÔªËØÖÊÁ¿·ÖÊýµÄ¼ÆËã¡¢¸ù¾ÝÎïÖʵÄÔªËØ×é³ÉºÍÖÊÁ¿È·¶¨ÎïÖʵĻ¯Ñ§Ê½¡¢»¯Ñ§·½³ÌʽµÄÊéдµÈ֪ʶ£¬ÖªÊ¶µã½Ï¶à£¬ÄѶÈÉÔ´ó£®½â´ðʱ±ØÐëÒªÉóºÃÌ⣬ÀíÇå˼·£¬Ï¸ÐÄ´ðÌ⣬±ÜÃâ³ö´í£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø