ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿½üÄêÀ´£¬ÎªÁ˱£»¤»·¾³£¬ÎÒ¹ú¸ÖÌúú̿ÐÐÒµ¡°È¥²úÄÜ¡±Ð§¹ûÃ÷ÏÔ¡£

£¨1£©Èý´ó»¯Ê¯È¼ÁÏÊÇú¡¢Ê¯ÓͺÍ____¡£¾Æ¾«Ò²Êdz£¼ûµÄȼÁÏ£¬Ð´³ö¾Æ¾«È¼ÉյĻ¯Ñ§·½³Ìʽ_________¡£

£¨2£©¹¤ÒµÉÏÓÃÒ»Ñõ»¯Ì¼ºÍ³àÌú¿óÁ¶ÌúµÄ»¯Ñ§·½³ÌʽΪ_________________¡£

£¨3£©ÃºÌ¿¡°È¥²úÄÜ¡±ÊÇָΪÁ˽â¾öú̿Éú²ú¹ýÊ££¬´Ó¶ø¶ÔÆóÒµÉú²úÄÜÁ¦½øÐÐÕû¸Ä¡£ÏÂÁÐ×ö·¨ÓÐÀûÓÚú¿óÐÐÒµ¡°È¥²úÄÜ¡±µÄÊÇ____________¡££¨ÌîÐòºÅ£©

A£®¹Ø±ÕһЩ¼¼ÊõÂäºóµÄСú¿óÒµ£¬¼õÉÙú̿²úÁ¿ B£®½«Ò»Ð©Ãº¿óÆóҵתÐÍΪÐÂÄÜÔ´ÆóÒµ

C£®È«Ãæ½ûÖ¹Éú²úú̿

¡¾´ð°¸¡¿ ÌìÈ»Æø C2H5OH+3O2 2CO2+3H2O Fe2O3+3CO 2Fe+3CO2 AB

¡¾½âÎö¡¿£¨1£©Èý´ó»¯Ê¯È¼ÁÏÊÇú¡¢Ê¯ÓͺÍÌìÈ»Æø£¬¾Æ¾«È¼ÉÕÉú³ÉË®ºÍ¶þÑõ»¯Ì¼£¬»¯Ñ§·½³ÌʽΪ£ºC2H5OH+3O22CO2+3H2O£»£¨2£©¹¤ÒµÉÏÓÃÒ»Ñõ»¯Ì¼ºÍ³àÌú¿óÁ¶ÌúµÄ»¯Ñ§·½³ÌʽΪ£ºFe2O3+3CO2Fe+3CO2£»£¨3£©ÃºÌ¿¡°È¥²úÄÜ¡±ÊÇָΪÁ˽â¾öú̿Éú²ú¹ýÊ££¬´Ó¶ø¶ÔÆóÒµÉú²úÄÜÁ¦½øÐÐÕû¸Ä¡£ÏÂÁÐ×ö·¨ÓÐÀûÓÚú¿óÐÐÒµ¡°È¥²úÄÜ¡±µÄÊÇ£ºA¡¢¹Ø±ÕһЩ¼¼ÊõÂäºóµÄСú¿óÒµ£¬¼õÉÙú̿²úÁ¿£¬ÕýÈ·£»B¡¢½«Ò»Ð©Ãº¿óÆóҵתÐÍΪÐÂÄÜÔ´ÆóÒµ£¬ÕýÈ·£»C¡¢È«Ãæ½ûÖ¹Éú²úú̿£¬²»¿ÉÐУ¬´íÎó¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø