题目内容

计算.
2009×
2009
2010
24×(
5
6
-
1
4
+
2
3
(3.12+0.9)÷[(1-0.4)÷0.1]
(4.7+3
2
5
)÷[(4
1
7
-3.5)×2
1
3
]
2
3
χ-1=0.9×
2
3
1
9
2
3
=8:χ
(1)2009×
2009
2010

=(2010-1)×
2009
2010

=2010×
2009
2010
-
2009
2010

=2009-
2009
2010

=2008
1
2010


(2)24×(
5
6
-
1
4
+
2
3

=24×
5
6
-24×
1
4
+24×
2
3

=20-6+16,
=30;

(3)(3.12+0.9)÷[(1-0.4)÷0.1]
=4.02÷[0.6÷0.1],
=4.02÷6,
=0.67;

(4)(4.7+3
2
5
)÷[(4
1
7
-3.5)×2
1
3
]
=(4.7+3.4)÷[(
29
7
-
7
2
)×
7
3
],
=8.1÷[(
58
14
-
49
14
)×
7
3
],
=8.1÷[
9
14
×
7
3
],
=8.1×
2
3

=5.4;

(5)
2
3
χ-1=0.9×
2
3

2
3
x-1=0.6,
2
3
x÷
2
3
=1.6÷
2
3

x=2.4;

(6)
1
9
2
3
=8:χ
1
9
x=
2
3
×8,
1
9
x÷
1
9
=
2
3
×8÷
1
9

x=48.
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网