题目内容
对于任意两个数x和y,定义新运算◆和?,规则如下:
x◆y=
,x?y=
;如 1◆2=
,1?2=
=
=1
,由此计算0.
◆(4?1
)=
.
x◆y=
| 2x+y |
| x+2y |
| x×y |
| x+y÷3 |
| 2×1+2 |
| 1+2×2 |
| 1×2 | ||
1+
|
| 6 |
| 5 |
| 1 |
| 5 |
| ? |
| 3 |
| ? |
| 6 |
| 1 |
| 2 |
| 17 |
| 25 |
| 17 |
| 25 |
分析:根据所给出的式子,得出新的运算方法,再利用新的运算方法计算0.
◆(4?1
)的值.
| ? |
| 3 |
| ? |
| 6 |
| 1 |
| 2 |
解答:解:(4?1
)=
=
=
,
而0.
=
,
0.
◆(4?1
)=
◆
,
=
,
=
÷
,
=
×
,
=
,
故答案为:
.
| 1 |
| 2 |
| 4×1.5 |
| 4+0.5 |
| 6 |
| 4.5 |
| 4 |
| 3 |
而0.
| ? |
| 3 |
| ? |
| 6 |
| 4 |
| 11 |
0.
| ? |
| 3 |
| ? |
| 6 |
| 1 |
| 2 |
| 4 |
| 11 |
| 4 |
| 3 |
=
2×
| ||||
|
=
| 68 |
| 33 |
| 100 |
| 33 |
=
| 68 |
| 33 |
| 33 |
| 100 |
=
| 17 |
| 25 |
故答案为:
| 17 |
| 25 |
点评:解答此题的关键是将循环小数化为分数,再根据新的运算方法列式解答.
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