题目内容
| 1 |
| 3 |
| 1 |
| 8 |
| 1 |
| 15 |
| 1 |
| 120 |
分析:把
看成是:
×(1-
),把
看成是:
×(
-
),…,依此类推,把
看成
×(
-
).然后提取
,原式变为
×(1-
+
-
+
-
+…+
-
+
-
).注意到从
开始,每隔两项就可以抵消,所以,原式变为
×(1+
-
-
),计算即可.
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 8 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 120 |
| 1 |
| 2 |
| 1 |
| 48 |
| 1 |
| 50 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 9 |
| 1 |
| 11 |
| 1 |
| 10 |
| 1 |
| 12 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 11 |
| 1 |
| 12 |
解答:解:
+
+
+…+
,
=
×(1-
+
-
+
-
+…+
-
+
-
),
=
×(1+
-
-
),
=
×
,
=
.
| 1 |
| 3 |
| 1 |
| 8 |
| 1 |
| 15 |
| 1 |
| 120 |
=
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 9 |
| 1 |
| 11 |
| 1 |
| 10 |
| 1 |
| 12 |
=
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 11 |
| 1 |
| 12 |
=
| 1 |
| 2 |
| 175 |
| 132 |
=
| 175 |
| 264 |
点评:解答此题应注意观察,认真分析式中数据,运用拆项的方法,进行简算.
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