题目内容
如图所示,矩形ABCD的面积为48,E是AB的四等分点,F是BC的三等分点,G是CD的中点,则三角形EFG的面积是______.

设AB=X,BC=Y则S=XY=48,
S三角形EFG=XY-(
×
x×
y+
×
y×
x+
×
x×y+
x×y),
=xy-
xy,
=
xy,
=
×48,
=16.
答:三角形EFG的面积是 16.
故答案为:16.
S三角形EFG=XY-(
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 3 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
=xy-
| 2 |
| 3 |
=
| 1 |
| 3 |
=
| 1 |
| 3 |
=16.
答:三角形EFG的面积是 16.
故答案为:16.
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