题目内容
(2008?金阊区)用递等式计算(能简算的就用简便方法计算)
3.72×3.5+3.5×6.28
0.25×16.2×4
(
-
)÷
+
×
÷4.
3.72×3.5+3.5×6.28
0.25×16.2×4
(
| 1 |
| 9 |
| 1 |
| 12 |
| 1 |
| 36 |
| 5 |
| 12 |
| 5 |
| 16 |
| 1 |
| 5 |
分析:(1)(3)运用乘法分配律(1)化原式=3.5×(3.72+6.28),(3)化原式=
×36-
×36解答,
(2)运用乘法交换律化原式=0.25×4×16.2解答,
(4)依据四则运算计算方法解答.
| 1 |
| 9 |
| 1 |
| 12 |
(2)运用乘法交换律化原式=0.25×4×16.2解答,
(4)依据四则运算计算方法解答.
解答:解:(1)3.72×3.5+3.5×6.28,
=3.5×(3.72+6.28),
=3.5×10,
=35;
(2)0.25×16.2×4,
=0.25×4×16.2,
=1×16.2,
=16.2;
(3)(
-
)÷
,
=
×36-
×36,
=4-3,
=1;
(4)
+
×
÷4,
=
+
÷4,
=
+
,
=
.
=3.5×(3.72+6.28),
=3.5×10,
=35;
(2)0.25×16.2×4,
=0.25×4×16.2,
=1×16.2,
=16.2;
(3)(
| 1 |
| 9 |
| 1 |
| 12 |
| 1 |
| 36 |
=
| 1 |
| 9 |
| 1 |
| 12 |
=4-3,
=1;
(4)
| 5 |
| 12 |
| 5 |
| 16 |
| 1 |
| 5 |
=
| 5 |
| 12 |
| 1 |
| 16 |
=
| 5 |
| 12 |
| 1 |
| 64 |
=
| 83 |
| 192 |
点评:本题主要考查学生对于乘法交换律,以及乘法分配律的灵活运用.
练习册系列答案
相关题目