题目内容
(2013?龙海市模拟)简算:
①
+
+
+…+
②102.31×59
③57.5-14.25-15
④
×102.31+40
×102.31.
①
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 199×200 |
②102.31×59
③57.5-14.25-15
| 3 |
| 4 |
④
| 1 |
| 7 |
| 6 |
| 7 |
分析:①每个分数都可以拆成两个分数相减的形式,然后通过加、减相抵消的方法,得出结果;
②把102.31看作100+2+0.3+0.01,然后运用乘法分配律计算;
③把分数化为小数,利用减法的性质简算;
④先运用乘法分配律的逆运算计算,得出41×102.31,再把102.31看作100+2+0.3=0.01,运用乘法分配律的逆运算简算.
②把102.31看作100+2+0.3+0.01,然后运用乘法分配律计算;
③把分数化为小数,利用减法的性质简算;
④先运用乘法分配律的逆运算计算,得出41×102.31,再把102.31看作100+2+0.3=0.01,运用乘法分配律的逆运算简算.
解答:解:①
+
+
+…+
,
=1-
+
-
+
+
+…
-
,
=1-
,
=
;
②102.31×59,
=(100+2+0.3+0.01)×59,
=100×59+2×59+0.3×59+0.01×59,
=5900+118+17.7+0.59,
=6036.29;
③57.5-14.25-15
,
=57.5-14.25-15.75,
=57.5-(14.25+15.75),
=57.5-30,
=27.5;
④
×102.31+40
×102.31,
=(
+
+40)×102.31,
=41×102.31,
=41×(100+2+0.3+0.01),
=4100+82+12.3+0.41,
=4194.71.
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 199×200 |
=1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 199 |
| 1 |
| 200 |
=1-
| 1 |
| 200 |
=
| 199 |
| 200 |
②102.31×59,
=(100+2+0.3+0.01)×59,
=100×59+2×59+0.3×59+0.01×59,
=5900+118+17.7+0.59,
=6036.29;
③57.5-14.25-15
| 3 |
| 4 |
=57.5-14.25-15.75,
=57.5-(14.25+15.75),
=57.5-30,
=27.5;
④
| 1 |
| 7 |
| 6 |
| 7 |
=(
| 1 |
| 7 |
| 6 |
| 7 |
=41×102.31,
=41×(100+2+0.3+0.01),
=4100+82+12.3+0.41,
=4194.71.
点评:此题考查了分数的拆项,以及运用运算定律简算的能力.
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