题目内容
(
-
)÷
+
÷□-
=1,则□=
| 7 |
| 12 |
| 1 |
| 4 |
| 5 |
| 9 |
| 2 |
| 3 |
| 1 |
| 5 |
1
| 1 |
| 9 |
1
.| 1 |
| 9 |
分析:我们运用等式的性质进行解答,即方程的两边同时加上或减去、除以或乘以不为0的数,等式仍然成立.
解答:解:(
-
)÷
+
÷□-
=1,
(
-
)×
+
÷□-
=1,
×
+
÷□-
=1,
+
÷□-
=1,
+
÷□=1,
-
+
÷□=1-
,
÷□=
,
□=
÷
,
□=
×
,
□=1
;
故答案为:1
.
| 7 |
| 12 |
| 1 |
| 4 |
| 5 |
| 9 |
| 2 |
| 3 |
| 1 |
| 5 |
(
| 7 |
| 12 |
| 3 |
| 12 |
| 9 |
| 5 |
| 2 |
| 3 |
| 1 |
| 5 |
| 4 |
| 12 |
| 9 |
| 5 |
| 2 |
| 3 |
| 1 |
| 5 |
| 3 |
| 5 |
| 2 |
| 3 |
| 1 |
| 5 |
| 2 |
| 5 |
| 2 |
| 3 |
| 2 |
| 5 |
| 2 |
| 5 |
| 2 |
| 3 |
| 2 |
| 5 |
| 2 |
| 3 |
| 3 |
| 5 |
□=
| 2 |
| 3 |
| 3 |
| 5 |
□=
| 2 |
| 3 |
| 5 |
| 3 |
□=1
| 1 |
| 9 |
故答案为:1
| 1 |
| 9 |
点评:本题考查了等式的基本性质,考查了学生的计算能力及对等式基本性质的运用情况.
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