题目内容
(1+
+
+…+
)×(
+
+…+
)-(1+
+
+…+
)×(
+
+…+
)．
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设
+
+…
=a，则：
（1+
+
+…
）×（
+
+…+
）-（1+
+
+…+
）×（
+
+…
）
=（1+a）（a+
）-（1+a+
）×a，
=a+
+a2+
-a-a2-
，
=
．
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（1+
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=（1+a）（a+
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=a+
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| a |
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=
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