题目内容
用递等式计算,能简便的要简便
| 60+40×3 | 125-25÷5 | 1100÷25÷4 |
| 672÷(24-12) | 120+78÷13 | 9000-271-729. |
考点:整数四则混合运算
专题:运算顺序及法则
分析:(1)先算乘法,再算加法;
(2)先算除法,再算减法;
(3)根据除法的性质简算;
(4)先算小括号里的减法,再算括号外的除法;
(5)先算除法,再算加法;
(6)根据减法的性质简算.
(2)先算除法,再算减法;
(3)根据除法的性质简算;
(4)先算小括号里的减法,再算括号外的除法;
(5)先算除法,再算加法;
(6)根据减法的性质简算.
解答:
解:(1)60+40×3
=60+120
=180;
(2)125-25÷5
=125-5
=120;
(3)1100÷25÷4
=1100÷(25×4)
=1100÷100
=11;
(4)672÷(24-12)
=672÷12
=56;
(5)120+78÷13
=120+6
=126;
(6)9000-271-729
=9000-(271+729)
=9000-1000
=8000.
=60+120
=180;
(2)125-25÷5
=125-5
=120;
(3)1100÷25÷4
=1100÷(25×4)
=1100÷100
=11;
(4)672÷(24-12)
=672÷12
=56;
(5)120+78÷13
=120+6
=126;
(6)9000-271-729
=9000-(271+729)
=9000-1000
=8000.
点评:本题考查了四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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