题目内容

用递等式计算.
4
5
×
5
18
+
3
7
+
7
9

7
8
÷[(
7
8
-
3
4
)×
4
5
]
7
3
-(
3
5
÷
9
20
+
1
3

6×(
2
15
+
1
12
)-
1
8
4
5
×
5
18
+
3
7
+
7
9

=
2
9
+
7
9
+
3
7

=1+
3
7

=1
3
7


7
8
÷[(
7
8
-
3
4
)×
4
5
]
=
7
8
÷[
1
8
×
4
5
],
=
7
8
×10,
=
35
4


7
3
-(
3
5
÷
9
20
+
1
3

=
7
3
-(
4
3
+
1
3
),
=
7
3
-
5
3

=
2
3


6×(
2
15
+
1
12
)-
1
8

=6×
13
60
-
1
8

=
13
10
-
1
8

=
47
40
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