题目内容
求未知数X:
1-
X=
X-
X=
4х+3×0.7=14.1.
1-
| 3 |
| 4 |
| 3 |
| 5 |
| 1 |
| 4 |
| 3 |
| 8 |
分析:(1)根据等式的性质,两边同加上
X,得
+
X=1,两边同减去
,再同乘
即可;
(2)运用乘法分配律改写成(1-
)X=
,即
X=
,再根据等式的性质,两边同乘
即可;
(3)先求出3×0.7=2.1,根据等式的性质,两边同减去2.1,再同除以4即可.
| 3 |
| 4 |
| 3 |
| 5 |
| 3 |
| 4 |
| 3 |
| 5 |
| 4 |
| 3 |
(2)运用乘法分配律改写成(1-
| 1 |
| 4 |
| 3 |
| 8 |
| 3 |
| 4 |
| 3 |
| 8 |
| 4 |
| 3 |
(3)先求出3×0.7=2.1,根据等式的性质,两边同减去2.1,再同除以4即可.
解答:解:(1)1-
X=
,
1-
X+
X=
+
X,
+
X=1,
+
X-
=1-
,
X=
,
X×
=
×
,
X=
;
(2)X-
X=
,
(1-
)X=
,
X=
,
X×
=
×
,
X=
;
(3)4х+3×0.7=14.1,
4х+2.1=14.1,
4х+2.1-2.1=14.1-2.1,
4x=12,
x÷4=12÷4,
x=3.
| 3 |
| 4 |
| 3 |
| 5 |
1-
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 5 |
| 3 |
| 4 |
| 3 |
| 5 |
| 3 |
| 4 |
| 3 |
| 5 |
| 3 |
| 4 |
| 3 |
| 5 |
| 3 |
| 5 |
| 3 |
| 4 |
| 2 |
| 5 |
| 3 |
| 4 |
| 4 |
| 3 |
| 2 |
| 5 |
| 4 |
| 3 |
X=
| 8 |
| 15 |
(2)X-
| 1 |
| 4 |
| 3 |
| 8 |
(1-
| 1 |
| 4 |
| 3 |
| 8 |
| 3 |
| 4 |
| 3 |
| 8 |
| 3 |
| 4 |
| 4 |
| 3 |
| 3 |
| 8 |
| 4 |
| 3 |
X=
| 1 |
| 2 |
(3)4х+3×0.7=14.1,
4х+2.1=14.1,
4х+2.1-2.1=14.1-2.1,
4x=12,
x÷4=12÷4,
x=3.
点评:在解方程时应根据等式的性质,即等式两边同加上、同减去或同乘上、同除以某一个数(0除外),等式的两边仍相等,同时注意等号上下要对齐.
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