题目内容
递等式计算
| 1456+398-956 | 784×8÷4 | 450+550÷2 |
| 872-321+279 | 6072÷6-386 | 358+286+152+314. |
考点:整数四则混合运算,运算定律与简便运算
专题:运算顺序及法则,运算定律及简算
分析:(1)(2)(4)按从左到右的运算顺序计算即可;
(3)(5)先算除法再算加减;
(6)根据加法的交换律与结合律简算.
(3)(5)先算除法再算加减;
(6)根据加法的交换律与结合律简算.
解答:
解:(1)1456+398-956
=1854-956
=898
(2)784×8÷4
=6272÷4
=1568
(3)450+550÷2
=450+275
=725
(4)872-321+279
=551+279
=830
(5)6072÷6-386
=1012-386
=626
(6)358+286+152+314
=(358+152)+(286+314)
=510+600
=1110
=1854-956
=898
(2)784×8÷4
=6272÷4
=1568
(3)450+550÷2
=450+275
=725
(4)872-321+279
=551+279
=830
(5)6072÷6-386
=1012-386
=626
(6)358+286+152+314
=(358+152)+(286+314)
=510+600
=1110
点评:计算四则混合运算时,要按照运算顺序,先算乘除,后算加减,有括号的先算括号里面的,再算括号外面的.能简算的要简算.
练习册系列答案
相关题目