题目内容
求未知数x
①
x=100×
②
x+
x=
③﹙1-
﹚x=180
④
×5+
x=8.
①
| 2 |
| 3 |
| 3 |
| 5 |
②
| 3 |
| 4 |
| 2 |
| 3 |
| 5 |
| 6 |
③﹙1-
| 3 |
| 5 |
④
| 6 |
| 5 |
| 6 |
| 5 |
分析:(1)题根据等式的性质,方程两边同时除以
来解;
(2)题先化简,然后根据等式的性质,方程两边同时除以
来解;
(3)题先化简,然后根据等式的性质,方程两边同时除以
来解;
(4)题先化简,然后根据等式的性质,方程两边同时减去6,再同时除以
来解.
| 2 |
| 3 |
(2)题先化简,然后根据等式的性质,方程两边同时除以
| 17 |
| 12 |
(3)题先化简,然后根据等式的性质,方程两边同时除以
| 2 |
| 5 |
(4)题先化简,然后根据等式的性质,方程两边同时减去6,再同时除以
| 6 |
| 5 |
解答:解:(1)
x=100×
x=60,
x÷
=60÷
,
x=90;
(2)
x+
x=
x=
,
x÷
=
÷
,
x=
;
(3)(1-
)x=180
x=180,
x÷
=180÷
,
x=450;
(4)
×5+
x=8
6+
x=8,
6+
x-6=8-6,
x=2,
x÷
=2÷
,
x=1
.
| 2 |
| 3 |
| 3 |
| 5 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
x=90;
(2)
| 3 |
| 4 |
| 2 |
| 3 |
| 5 |
| 6 |
| 17 |
| 12 |
| 5 |
| 6 |
| 17 |
| 12 |
| 17 |
| 12 |
| 5 |
| 6 |
| 17 |
| 12 |
x=
| 10 |
| 17 |
(3)(1-
| 3 |
| 5 |
| 2 |
| 5 |
| 2 |
| 5 |
| 2 |
| 5 |
| 2 |
| 5 |
x=450;
(4)
| 6 |
| 5 |
| 6 |
| 5 |
6+
| 6 |
| 5 |
6+
| 6 |
| 5 |
| 6 |
| 5 |
| 6 |
| 5 |
| 6 |
| 5 |
| 6 |
| 5 |
x=1
| 2 |
| 3 |
点评:利用等式的性质解方程,注意等号对齐.
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