题目内容
(2010?中山市)每题都要有必要的计算过程.
①23×2424-24×2323
②52.44×79.45+159×47.56+79.55×52.44
③18×
+0.65×
-
×18+
÷1
④2.75+
-1.4+2
÷
-87.5%
⑤
+
.
①23×2424-24×2323
②52.44×79.45+159×47.56+79.55×52.44
③18×
| 3 |
| 7 |
| 8 |
| 13 |
| 2 |
| 7 |
| 5 |
| 13 |
| 7 |
| 13 |
④2.75+
| 5 |
| 12 |
| 1 |
| 4 |
| 5 |
| 12 |
⑤
| 2010×2008+1 |
| 2009 |
| 2009+2010×2008 |
| 2009×2010-1 |
分析:(1)化23×2424=23×24×101,24×2323=24×23×101即可解答
(2)运用乘法分配律解答,
(3)按照先算第二级运算,再算第一级运算的顺序解答,
(4)按照先算第二级运算,再从左到右顺序解答,
(5)运用乘法分配律化2010×2008=2009×2008+2008,2009+2010×2008=2009+2009×2008+2008=2009×2009,2009×2010-1=2009×2009+2009-1即可解答.
(2)运用乘法分配律解答,
(3)按照先算第二级运算,再算第一级运算的顺序解答,
(4)按照先算第二级运算,再从左到右顺序解答,
(5)运用乘法分配律化2010×2008=2009×2008+2008,2009+2010×2008=2009+2009×2008+2008=2009×2009,2009×2010-1=2009×2009+2009-1即可解答.
解答:解:①23×2424-24×2323
=23×24×101-24×23×101
=0;
②52.44×79.45+159×47.56+79.55×52.44
=52.44×(79.45+79.55)+159×47.56
=52.44×159+159×47.56
=159×(52.44+47.56)
=159×100
=15900;
③18×
+0.65×
-
×18+
÷1
=
+
-
+
=(
-
)+(
+
)
=3
+
=3
;
④2.75+
-1.4+2
÷
-87.5%
=2.75+
-1.4+5.4-87.5%
=3
-1.4+5.4-87.5%
=3
+4-87.5%
=6
;
⑤
+
=
+
=
+
=2009+1
=2010.
=23×24×101-24×23×101
=0;
②52.44×79.45+159×47.56+79.55×52.44
=52.44×(79.45+79.55)+159×47.56
=52.44×159+159×47.56
=159×(52.44+47.56)
=159×100
=15900;
③18×
| 3 |
| 7 |
| 8 |
| 13 |
| 2 |
| 7 |
| 5 |
| 13 |
| 7 |
| 13 |
=
| 54 |
| 7 |
| 2 |
| 5 |
| 32 |
| 7 |
| 1 |
| 4 |
=(
| 54 |
| 7 |
| 32 |
| 7 |
| 2 |
| 5 |
| 1 |
| 4 |
=3
| 1 |
| 7 |
| 13 |
| 20 |
=3
| 111 |
| 140 |
④2.75+
| 5 |
| 12 |
| 1 |
| 4 |
| 5 |
| 12 |
=2.75+
| 5 |
| 12 |
=3
| 1 |
| 6 |
=3
| 1 |
| 6 |
=6
| 7 |
| 24 |
⑤
| 2010×2008+1 |
| 2009 |
| 2009+2010×2008 |
| 2009×2010-1 |
=
| 2009×2008+2008+1 |
| 2009 |
| 2009+2008×2009+2008 |
| 2009×(2009+1)-1 |
=
| 2009×(2008+1) |
| 2009 |
| 2009×(2008+1)+2008 |
| 2009×2009+2008 |
=2009+1
=2010.
点评:本题主要考查学生依据四则运算计算方法,以及正确运用简便方法解决问题的能力.
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