题目内容
计算:
①4050-6030÷ =3900
②3×6+33×66+333×666=
③1-
+
-
+
-
=
④方程:10.1-17X=1.86-15解是X=
⑤1÷(2÷3)÷(3÷4)÷(4÷5)÷…÷(19÷20)=
⑥3
×(3
+
)+3.4×
=
①4050-6030÷
②3×6+33×66+333×666=
③1-
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 4 |
| 4 |
| 5 |
| 5 |
| 6 |
④方程:10.1-17X=1.86-15解是X=
⑤1÷(2÷3)÷(3÷4)÷(4÷5)÷…÷(19÷20)=
⑥3
| 2 |
| 5 |
| 4 |
| 11 |
| 5 |
| 17 |
| 7 |
| 11 |
分析:算式①可根据加法与减法、乘法与除法的互逆关系计算;
算式②可将式中的乘法算式分解为具有共同因数3×6的算式后再根据乘法分配律计算;
算式③可将原式分解为1-
+1-
-(1-
)+1-
-(1-
)进行计算;
算式④可根据等式的性质进行解方程:方程的两边同时加上、减去、乘以、或除以同一个数,等式仍然成立;
算式⑤可根据除以一个数等于乘以这个数的倒数的计算法则,将除法算式化为乘法算式后通过约分计算,即原式=1×
×
×
×…
;
算式⑥可根据乘法分配律进行计算.
算式②可将式中的乘法算式分解为具有共同因数3×6的算式后再根据乘法分配律计算;
算式③可将原式分解为1-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 6 |
算式④可根据等式的性质进行解方程:方程的两边同时加上、减去、乘以、或除以同一个数,等式仍然成立;
算式⑤可根据除以一个数等于乘以这个数的倒数的计算法则,将除法算式化为乘法算式后通过约分计算,即原式=1×
| 3 |
| 2 |
| 4 |
| 3 |
| 5 |
| 4 |
| 20 |
| 19 |
算式⑥可根据乘法分配律进行计算.
解答:解:①6030÷(4050-3900)
=6030÷150,
=40.2;
所以4050-6030÷40.2=3900;
②3×6+33×66+333×666
=3×6+11×3×11×6+111×3×111×6,
=(1+11×11+111×111)×3×6,
=12443×18,
=223974;
③1-
+
-
+
-
=1-
+1-
-(1-
)+1-
-(1-
)
=1-
+1-
-1+
+1-
-1+
,
=
-
+
-
+
,
=
;
④10.1-17X=1.86-15
10.1-17X+15=1.86-15+15
25.1-17X=1.86
25.1-17X+17X=1.86+17X
25.1-1.86=1.86+17X-1.86
23.24=17X
X=
;
⑤1÷(2÷3)÷(3÷4)÷(4÷5)÷…÷(19÷20)
=1÷
÷
÷…÷
,
=1×
×
×
×…
,
=10;
⑥3
×(3
+
)+3.4×
=
×3
+
×
+
×
,
=(3
+
)×
+1,
=4×
+1,
=13.6+1,
=14.6.
=6030÷150,
=40.2;
所以4050-6030÷40.2=3900;
②3×6+33×66+333×666
=3×6+11×3×11×6+111×3×111×6,
=(1+11×11+111×111)×3×6,
=12443×18,
=223974;
③1-
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 4 |
| 4 |
| 5 |
| 5 |
| 6 |
=1-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 6 |
=1-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 6 |
=
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 6 |
=
| 23 |
| 60 |
④10.1-17X=1.86-15
10.1-17X+15=1.86-15+15
25.1-17X=1.86
25.1-17X+17X=1.86+17X
25.1-1.86=1.86+17X-1.86
23.24=17X
X=
| 581 |
| 425 |
⑤1÷(2÷3)÷(3÷4)÷(4÷5)÷…÷(19÷20)
=1÷
| 2 |
| 3 |
| 3 |
| 4 |
| 19 |
| 20 |
=1×
| 3 |
| 2 |
| 4 |
| 3 |
| 5 |
| 4 |
| 20 |
| 19 |
=10;
⑥3
| 2 |
| 5 |
| 4 |
| 11 |
| 5 |
| 17 |
| 7 |
| 11 |
=
| 17 |
| 5 |
| 4 |
| 11 |
| 17 |
| 5 |
| 5 |
| 17 |
| 17 |
| 5 |
| 7 |
| 11 |
=(3
| 4 |
| 11 |
| 7 |
| 11 |
| 17 |
| 5 |
=4×
| 17 |
| 5 |
=13.6+1,
=14.6.
点评:本题式中数据较为复杂,完成时要细心,运用合适的方法进行计算.
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