题目内容
解方程
3x-
=
5x+(1-
)=
+x=
.
3x-
| 5 |
| 8 |
| 3 |
| 8 |
5x+(1-
| 2 |
| 9 |
| 7 |
| 9 |
| 1 |
| 4 |
| 7 |
| 8 |
分析:(1)根据等式的性质,两边同加上
,再通除以即可;
(2)先求出1-
=
,原式变为5x+
=
,根据等式的性质,两边同减去
,得5x=0,故x=0;
(3)根据等式的性质,两边同减去
即可.
| 5 |
| 8 |
(2)先求出1-
| 2 |
| 9 |
| 7 |
| 9 |
| 7 |
| 9 |
| 7 |
| 9 |
| 7 |
| 9 |
(3)根据等式的性质,两边同减去
| 1 |
| 4 |
解答:解:(1)3x-
=
,
3x-
+
=
+
,
3x=1,
x=
;
(2)5x+(1-
)=
,
5x+
=
,
5x+
-
=
-
,
5x=0,
x=0;
(3)
+x=
,
+x-
=
-
,
x=
.
| 5 |
| 8 |
| 3 |
| 8 |
3x-
| 5 |
| 8 |
| 5 |
| 8 |
| 3 |
| 8 |
| 5 |
| 8 |
3x=1,
x=
| 1 |
| 3 |
(2)5x+(1-
| 2 |
| 9 |
| 7 |
| 9 |
5x+
| 7 |
| 9 |
| 7 |
| 9 |
5x+
| 7 |
| 9 |
| 7 |
| 9 |
| 7 |
| 9 |
| 7 |
| 9 |
5x=0,
x=0;
(3)
| 1 |
| 4 |
| 7 |
| 8 |
| 1 |
| 4 |
| 1 |
| 4 |
| 7 |
| 8 |
| 1 |
| 4 |
x=
| 5 |
| 8 |
点评:此题考查了根据等式的性质解方程,即等式两边同加、同减、同乘或同除以一个数(0除外),等式的左右两边仍相等;注意等号上下要对齐.
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