题目内容
递等式计算:
| 360-225÷15×18 | 4.72-1.16-2.84 |
解:(1)360-225÷15×18,
=360-15×18,
=360-270,
=90;
(2)
÷
×
,
=
×
,
=
;
(3)4.72-1.16-2.84,
=4.72-(1.16+2.84),
=4.72-4,
=0.72;
(4)
+
÷
+
,
=
+
+
,
=
+
+
,
=1+
,
=1
.
分析:(1)先算除法,再算乘法,最后算减法;
(2)按照从左到右的顺序计算;
(3)根据减法的性质简算;
(4)先算除法,再根据加法交换律简算.
点评:此题主要考查分数、整数、小数的四则混合运算的运算顺序和应用运算定律进行简便计算.
=360-15×18,
=360-270,
=90;
(2)
=
=
(3)4.72-1.16-2.84,
=4.72-(1.16+2.84),
=4.72-4,
=0.72;
(4)
=
=
=1+
=1
分析:(1)先算除法,再算乘法,最后算减法;
(2)按照从左到右的顺序计算;
(3)根据减法的性质简算;
(4)先算除法,再根据加法交换律简算.
点评:此题主要考查分数、整数、小数的四则混合运算的运算顺序和应用运算定律进行简便计算.
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