题目内容
用递等式计算.
360÷15-2.5×1.6
÷
-
×6
(1-
×
)÷
.
360÷15-2.5×1.6
8 |
15 |
1 |
6 |
7 |
15 |
(1-
3 |
4 |
2 |
5 |
7 |
8 |
分析:(1)360÷15-2.5×1.6,按运算顺序进行计算,先算除法和乘法,再算减法.在算2.5×1.6时,可把1.6拆成4×0.4,进行简算;
(2)
÷
-
×6,先把除法改为乘法,然后用乘法分配律的逆运算简算;
(3)(1-
×
)÷
,按运算顺序进行计算,先算括号里的,再算括号外的.
(2)
8 |
15 |
1 |
6 |
7 |
15 |
(3)(1-
3 |
4 |
2 |
5 |
7 |
8 |
解答:解:(1)360÷15-2.5×1.6,
=24-2.5×4×0.4,
=24-10×0.4,
=24-4,
=20;
(2)
÷
-
×6,
=
×6-
×6
=(
-
)×6,
=
×6,
=
;
(3)(1-
×
)÷
,
=(1-
)÷
,
=
×
,
=
.
=24-2.5×4×0.4,
=24-10×0.4,
=24-4,
=20;
(2)
8 |
15 |
1 |
6 |
7 |
15 |
=
8 |
15 |
7 |
15 |
=(
8 |
15 |
7 |
15 |
=
1 |
15 |
=
3 |
5 |
(3)(1-
3 |
4 |
2 |
5 |
7 |
8 |
=(1-
3 |
10 |
7 |
8 |
=
7 |
10 |
8 |
7 |
=
4 |
5 |
点评:此题重点考查学生对四则混合运算顺序的掌握情况,以及简算的能力.
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