题目内容
用递等式计算:
360+612÷12
(200-1456÷26)×24
8+0.68-0.36
2790÷(250×12-2991)
360+612÷12
(200-1456÷26)×24
8+0.68-0.36
2790÷(250×12-2991)
分析:(1)先算除法,再算加法;
(2)先算小括号里面的除法,再算小括号里面的减法,最后算括号外的乘法;
(3)按照从左到右的顺序计算;
(4)先算小括号里面的乘法,再算小括号里面的减法,再算括号外的除法.
(2)先算小括号里面的除法,再算小括号里面的减法,最后算括号外的乘法;
(3)按照从左到右的顺序计算;
(4)先算小括号里面的乘法,再算小括号里面的减法,再算括号外的除法.
解答:解:(1)360+612÷12,
=360+51,
=411;
(2)(200-1456÷26)×24,
=(200-56)×24,
=144×24,
=3456;
(3)8+0.68-0.36,
=8.68-0.36,
=8.32;
(4)2790÷(250×12-2991),
=2790÷(3000-2991),
=2790÷9,
=310.
=360+51,
=411;
(2)(200-1456÷26)×24,
=(200-56)×24,
=144×24,
=3456;
(3)8+0.68-0.36,
=8.68-0.36,
=8.32;
(4)2790÷(250×12-2991),
=2790÷(3000-2991),
=2790÷9,
=310.
点评:本题考查了简单的四则混合运算,计算时先理清楚运算顺序,根据运算顺序逐步求解即可.

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