题目内容

化简.
(1)
0.2+0.3+0.4+0.5
0.2×0.3×0.4×0.5

(2)2
2
15
÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6.
分析:(1)分子分母同时计算,然后相除即可;
(2)先算括号内的,再算括号外的除法和乘法,最后算加法;
(3)先算小括号内的,再算中括号内的,最后算乘法.
解答:解:(1)
0.2+0.3+0.4+0.5
0.2×0.3×0.4×0.5

=
1.4
0.012

=116
2
3


(2)2
2
15
÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
点评:完成此题,注意运算顺序与数字转化,灵活计算.
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