题目内容
(2013?北京模拟)1.8×2
÷16.9÷(3
×1.16)×1.3.
| 8 |
| 25 |
| 3 |
| 5 |
分析:先算小括号里面的乘法,再运用乘法交换律以及除法的性质简算.
解答:解:(1)1.8×2
÷16.9÷(3
×1.16)×1.3,
=1.8×2
÷16.9÷4.176×1.3,
=4.176÷16.9÷4.176×1.3,
=4.176÷4.176×1.3÷16.9,
=1×1.3÷16.9,
=1.3÷16.9,
=
.
| 8 |
| 25 |
| 3 |
| 5 |
=1.8×2
| 8 |
| 25 |
=4.176÷16.9÷4.176×1.3,
=4.176÷4.176×1.3÷16.9,
=1×1.3÷16.9,
=1.3÷16.9,
=
| 1 |
| 13 |
点评:本题较复杂,完成本题要注意分析式中数据,运用合适的简便方法计算.
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