题目内容
解方程.
x+
=
X-
X=
15×
÷X=
.
| 8 |
| 9 |
| 1 |
| 15 |
| 4 |
| 5 |
| 2 |
| 3 |
| 2 |
| 9 |
| 3 |
| 5 |
| 2 |
| 3 |
考点:方程的解和解方程
专题:简易方程
分析:(1)根据等式的性质,两边同减去
再同乘上
即可;
(2)先化简方程得
X=
,再根据等式的性质,两边乘上3即可;
(3)先化简方程得9÷X=
,再根据等式的性质,两边同乘上X得
X=9,两边再同乘上
即可.
| 1 |
| 15 |
| 9 |
| 8 |
(2)先化简方程得
| 1 |
| 3 |
| 2 |
| 9 |
(3)先化简方程得9÷X=
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 2 |
解答:
解:(1)
x+
=
x+
-
=
-
x=
x×
=
×
x=
;
(2)X-
X=
X=
X×3=
×3
X=
;
(3)15×
÷X=
9÷X=
9÷X×X=
×X
X=9
X×
=9×
X=
.
| 8 |
| 9 |
| 1 |
| 15 |
| 4 |
| 5 |
| 8 |
| 9 |
| 1 |
| 15 |
| 1 |
| 15 |
| 4 |
| 5 |
| 1 |
| 15 |
| 8 |
| 9 |
| 11 |
| 15 |
| 8 |
| 9 |
| 9 |
| 8 |
| 11 |
| 15 |
| 9 |
| 8 |
x=
| 33 |
| 40 |
(2)X-
| 2 |
| 3 |
| 2 |
| 9 |
| 1 |
| 3 |
| 2 |
| 9 |
| 1 |
| 3 |
| 2 |
| 9 |
X=
| 2 |
| 3 |
(3)15×
| 3 |
| 5 |
| 2 |
| 3 |
9÷X=
| 2 |
| 3 |
9÷X×X=
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 2 |
| 3 |
| 2 |
X=
| 27 |
| 2 |
点评:此题考查了根据等式的性质解方程,即方程两边同加、同减、同乘或同除以某数(0除外),方程的左右两边仍相等;注意“=”号上下要对齐.
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