题目内容
用递等式计算
12×(53+147×4)
985-400÷80×4
(84+14)×(210÷3)
[175-(49+26)]×15.
12×(53+147×4)
985-400÷80×4
(84+14)×(210÷3)
[175-(49+26)]×15.
分析:(1)按照先算括号里面的乘法,再算括号里面的加法,最后算括号外面的顺序解答,
(2)按照先算除法,再算乘法,最后算减法顺序解答,
(3)按照先同时计算括号里面的,再算括号外面的顺序解答,
(4)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序解答.
(2)按照先算除法,再算乘法,最后算减法顺序解答,
(3)按照先同时计算括号里面的,再算括号外面的顺序解答,
(4)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序解答.
解答:解:(1)12×(53+147×4)
=12×(53+588)
=12×641
=7692;
(2)985-400÷80×4
=985-5×4
=985-20
=965;
(3)(84+14)×(210÷3)
=98×70
=6860;
(4)[175-(49+26)]×15
=[175-75]×15
=100×15
=1500.
=12×(53+588)
=12×641
=7692;
(2)985-400÷80×4
=985-5×4
=985-20
=965;
(3)(84+14)×(210÷3)
=98×70
=6860;
(4)[175-(49+26)]×15
=[175-75]×15
=100×15
=1500.
点评:本题考查知识点:依据四则运算顺序正确进行计算.
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