题目内容

灵活计算
①
1
3
-(
4
5
-
2
3
)
②75÷
5
3
=25×
3
5
③(
5
14
+
4
13
)×14-4÷13
④(
5
12
-
13
36
)÷
2
3
+
1
6
.
(1)
1
3
-(
4
5
-
2
3
)
,
=
1
3
-
4
5
+
2
3
,
=(
1
3
+
2
3
)-
4
5
,
=1-
4
5
,
=
1
5
;

(2)75÷
5
3
-25×
3
5
,
=75×
3
5
-25×
3
5
,
=(75-25)×
3
5
,
=50×
3
5
,
=30;

(3)(
5
14
+
4
13
)×14-4÷13
,
=
5
14
×14+
4
13
×14-
4
13
,
=5+(14-1)×
4
13
,
=5+13×
4
13
,
=5+4,
=9;

(4)(
5
12
-
13
36
)÷
2
3
+
1
6
,
=
1
18
÷
2
3
+
1
6
,
=
1
12
+
1
6
,
=
1
4
.
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