题目内容
| 求未知数x x+
|
|
|
|
分析:(1)原式变为(1+
)x=24,即
x=24,根据等式的性质,两边同乘
即可;
(2)原式变为
x=
×2,根据等式的性质,两边同乘5即可;
(3)先根据比例的性质改写成2x=5×1.8,根据等式的性质,两边同除以2即可;
(4)先根据比例的性质改写成
x=
×
,再根据等式的性质,两边同乘2即可.
| 1 |
| 3 |
| 4 |
| 3 |
| 3 |
| 4 |
(2)原式变为
| 1 |
| 5 |
| 7 |
| 10 |
(3)先根据比例的性质改写成2x=5×1.8,根据等式的性质,两边同除以2即可;
(4)先根据比例的性质改写成
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 5 |
解答:解:(1)x+
x=24,
(1+
)x=24,
x=24,
x×
=24×
,
x=18;
(2)
x=70%÷
,
x=
×2,
x=
,
x×5=
×5,
x=7;
(3)
=
,
2x=5×1.8,
2x÷2=5×1.8÷2,
x=4.5;
(4)
:
=x:
,
x=
×
,
x×2=
×
×2,
x=
.
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| 3 |
(1+
| 1 |
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 3 |
| 4 |
| 3 |
| 4 |
x=18;
(2)
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| 5 |
| 1 |
| 2 |
| 1 |
| 5 |
| 7 |
| 10 |
| 1 |
| 5 |
| 7 |
| 5 |
| 1 |
| 5 |
| 7 |
| 5 |
x=7;
(3)
| x |
| 5 |
| 1.8 |
| 2 |
2x=5×1.8,
2x÷2=5×1.8÷2,
x=4.5;
(4)
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 5 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 5 |
x=
| 4 |
| 15 |
点评:此题考查了运用等式的性质解方程,即等式两边同加上或同减去、同乘上或同除以一个数(0除外),两边仍相等,同时注意“=”上下要对齐.
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