题目内容
脱式计算
15000-(720+14×15)÷31;
[68+132×(57-57)]÷68;
(379+146)÷[294÷(103-5)×25].
15000-(720+14×15)÷31;
[68+132×(57-57)]÷68;
(379+146)÷[294÷(103-5)×25].
考点:整数四则混合运算
专题:运算顺序及法则
分析:(1)先算乘法,再算加法,再算除法,最后算减法;
(2)先算减法,再算乘法,再算加法,最后算除法;
(3)先算加法和减法,再算中括号里面的除法,再算乘法,最后算括号外面的除法.
(2)先算减法,再算乘法,再算加法,最后算除法;
(3)先算加法和减法,再算中括号里面的除法,再算乘法,最后算括号外面的除法.
解答:
解:(1)15000-(720+14×15)÷31
=15000-(720+210)÷31
=15000-930÷31
=15000-30
=14970;
(2)[68+132×(57-57)]÷68
=[68+132×0]÷68
=[68+0]÷68
=68÷68
=1;
(3)(379+146)÷[294÷(103-5)×25]
=525÷[294÷98×25]
=525÷[3×25]
=525÷75
=7.
=15000-(720+210)÷31
=15000-930÷31
=15000-30
=14970;
(2)[68+132×(57-57)]÷68
=[68+132×0]÷68
=[68+0]÷68
=68÷68
=1;
(3)(379+146)÷[294÷(103-5)×25]
=525÷[294÷98×25]
=525÷[3×25]
=525÷75
=7.
点评:此题主要考查整数的四则混合运算的运算顺序,然后再进一步计算.
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