题目内容

7
÷3-
2
×
1
3
1
3
÷[4×(
2
-
3
4
)]
(2-
1
2
÷
3
4
)÷
2
3
1o×(
2
3
+
3
2
-
3
(口)
7
0
÷9-
3
0
×
9

=
7
0
×
9
-
3
0
×
9

=(
7
0
-
3
0
)×
9

=口×
9

=
9


(3)
x
÷[3×(
0
6
-
x
3
)],
=
x
÷[3×
口3
],
=
x
÷
x

=口;

(x)(3-
3
÷
x
3
)÷
3
9

=(3-
3
×
3
x
)÷
3
9

=(3-
3
x
)×
9
3

=
3
x
×
9
3

=6;

(3)口8×(
3
x
+
x
3
-
0
9
),
=口8×
3
x
+口8×
x
3
-口8×
0
9

=口3+37-口0,
=39.
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