题目内容

递等式计算.
(1)8×
5
6
+
2
5
÷4(2)(
1
3
-
1
4
)÷
1
2
+
5
6

(3)
5
8
÷(
1
6
+
3
4
×
5
6
)(4)[1-(
3
5
-
3
10
)]÷
7
8
.
(1)8×
5
6
+
2
5
÷4,
=
20
3
+
1
10
,
=6
23
30
,
(2)(
1
3
-
1
4
)÷
1
2
+
5
6
,
=
1
12
÷
1
2
+
5
6
,
=
1
6
+
5
6
,
=1,
(3)
5
8
÷(
1
6
+
3
4
×
5
6
),
=
5
8
÷(
1
6
+
5
8
),
=
5
8
÷
19
24
,
=
15
19
,
(4)[1-(
3
5
-
3
10
)]÷
7
8
,
=(1-
3
10
)÷
7
8
,
=
7
10
÷
7
8
,
=
4
5
.
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