题目内容
| 用递等式计算. (1)
| (2)48048÷12+88 | ||||||||
(3)9÷(
| (4)(1-0.8×
|
(1)
÷
×
,
=
×
,
=2;
(2)48048÷12+88,
=4004+88,
=4092;
(3)9÷(
-
)×3,
=9÷
×3,
=81×3,
=243;
(4)(1-0.8×
)÷
,
=(1-0.6)÷
,
=0.4÷
,
=0.5.
| 5 |
| 6 |
| 1 |
| 4 |
| 3 |
| 5 |
=
| 10 |
| 3 |
| 3 |
| 5 |
=2;
(2)48048÷12+88,
=4004+88,
=4092;
(3)9÷(
| 7 |
| 9 |
| 2 |
| 3 |
=9÷
| 1 |
| 9 |
=81×3,
=243;
(4)(1-0.8×
| 3 |
| 4 |
| 4 |
| 5 |
=(1-0.6)÷
| 4 |
| 5 |
=0.4÷
| 4 |
| 5 |
=0.5.
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