题目内容
一辆汽车从甲地开往乙地,第一天走350千米,第二天走的比第一天多20%,没走的比两天共走的多
,甲、乙两地相距多少千米?
| 1 |
| 14 |
350+350×(1+20%)+[350+350×(1+20%)]×(1+
)
=350+350×120%+[350+350×120%]×
,
=350+420+[350+420]×
,
=770+770×
,
=770+825,
=1595(千米).
答:甲、乙两地相距1595千米.
| 1 |
| 14 |
=350+350×120%+[350+350×120%]×
| 15 |
| 14 |
=350+420+[350+420]×
| 15 |
| 14 |
=770+770×
| 15 |
| 14 |
=770+825,
=1595(千米).
答:甲、乙两地相距1595千米.
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