题目内容
计算:1
+2
+3
+4
+5
+6
.
| 1 |
| 21 |
| 1 |
| 30 |
| 1 |
| 42 |
| 1 |
| 56 |
| 1 |
| 72 |
| 1 |
| 90 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:把带分数拆成整数和真分数两部分,然后整数与分数分别相加,除第一个分数外,再把每个真分数拆成两个分数相减的形式,进而得解.
解答:
解:1
+2
+3
+4
+5
+6
=(1+2+3+4+5+6)+(
+
+
+
+
+
)
=21+(
+
-
+
-
+
-
+
-
+
-
)
=21+(
+
-
)
=21+
=21
| 1 |
| 21 |
| 1 |
| 30 |
| 1 |
| 42 |
| 1 |
| 56 |
| 1 |
| 72 |
| 1 |
| 90 |
=(1+2+3+4+5+6)+(
| 1 |
| 21 |
| 1 |
| 30 |
| 1 |
| 42 |
| 1 |
| 56 |
| 1 |
| 72 |
| 1 |
| 90 |
=21+(
| 1 |
| 21 |
| 1 |
| 5 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 9 |
| 1 |
| 9 |
| 1 |
| 10 |
=21+(
| 1 |
| 21 |
| 1 |
| 5 |
| 1 |
| 10 |
=21+
| 31 |
| 210 |
=21
| 31 |
| 210 |
点评:此题解答的关键在于分数的巧妙拆分,通过加减相互抵消,求出结果.
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