题目内容
[(5
-4.25)×
]÷
+33÷
.
| 1 |
| 4 |
| 5 |
| 8 |
| 3 |
| 8 |
| 11 |
| 6 |
分析:加号两边同时计算,加号前边的算式先算小括号内的,再算中括号内的,然后算括号外的除法,最后算加法.
解答:解:[(5
-4.25)×
]÷
+33÷
,
=[(5.25-4.25)×
]÷
+33×
,
=[1×
]÷
+18,
=
×
+18,
=
+18,
=19
.
| 1 |
| 4 |
| 5 |
| 8 |
| 3 |
| 8 |
| 11 |
| 6 |
=[(5.25-4.25)×
| 5 |
| 8 |
| 3 |
| 8 |
| 6 |
| 11 |
=[1×
| 5 |
| 8 |
| 3 |
| 8 |
=
| 5 |
| 8 |
| 8 |
| 3 |
=
| 5 |
| 3 |
=19
| 2 |
| 3 |
点评:完成此题,应特别注意运算顺序,以及数字转化.
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