题目内容
[(1
×2+2.5)÷
-2
]÷1.6
[(5
-4.25)×
]÷
+33÷
[(9
-3.2)÷2
]×[1÷(2.1-2
)]
9.75+99.75+999.75+9999.75
1
-[(3.62×
+6.38÷7
)×1.82-1
×0.82]
.
2 |
3 |
7 |
8 |
1 |
5 |
[(5
1 |
4 |
5 |
8 |
3 |
8 |
11 |
6 |
[(9
1 |
5 |
1 |
2 |
9 |
100 |
9.75+99.75+999.75+9999.75
1
2 |
3 |
2 |
15 |
1 |
2 |
1 |
3 |
2890+
| ||||||
|
分析:①②③⑤根据分数的四则混合运算的顺序进行计算,先算括号内部的,再计算括号外面的.④我们先加上4个1凑成整十,再减去4,即可求出答案.
⑥把分式的形式写成横式的形式然后运用乘法的分配律进行计算.
⑥把分式的形式写成横式的形式然后运用乘法的分配律进行计算.
解答:解:①[(1
×2+2.5)÷
-2
]÷1.6,
=[(
+
)×
-
]÷1.6,
=[(
+
)×
-
]×
,
=[
×
-
]×
,
=[
-
]×
,
=[
-
]×
,
=
×
,
=
,
=2
;
②[(5
-4.25)×
]÷
+33÷
,
=
×
+33×
,
=
+18,
=19
;
③[(9
-3.2)÷2
]×[1÷(2.1-2
)],
=[6×
]×[1÷
],
=
×100,
=240;
④9.75+99.75+999.75+9999.75
=(9+1)+(99+1)+(999+1)+(9999+1)-4+0.75×4,
=10+100+1000+10000-4+3,
=11110-1,
=11109;
⑤1
-[(3.62×
+6.38÷7
)×1.82-1
×0.82],
=1
-[(3.62×
+6.38×
)×1.82-
×0.82],
=1
-[
×(3.62+6.38)×1.82-
×0.82],
=1
-[
×(1.82-0.82)],
=1
-
,
=
;
⑥
,
=(2890+
+
+
)÷(
+
+
),
=(2890+
)×
,
=2890×
+
×
,
=1200+1,
=1201.
2 |
3 |
7 |
8 |
1 |
5 |
=[(
10 |
3 |
15 |
6 |
8 |
7 |
11 |
5 |
=[(
20 |
6 |
15 |
6 |
8 |
7 |
11 |
5 |
5 |
8 |
=[
35 |
6 |
8 |
7 |
11 |
5 |
5 |
8 |
=[
20 |
3 |
11 |
5 |
5 |
8 |
=[
100 |
15 |
33 |
15 |
5 |
8 |
=
67 |
15 |
5 |
8 |
=
67 |
24 |
=2
19 |
24 |
②[(5
1 |
4 |
5 |
8 |
3 |
8 |
11 |
6 |
=
5 |
8 |
8 |
3 |
6 |
11 |
=
5 |
3 |
=19
2 |
3 |
③[(9
1 |
5 |
1 |
2 |
9 |
100 |
=[6×
2 |
5 |
1 |
100 |
=
12 |
5 |
=240;
④9.75+99.75+999.75+9999.75
=(9+1)+(99+1)+(999+1)+(9999+1)-4+0.75×4,
=10+100+1000+10000-4+3,
=11110-1,
=11109;
⑤1
2 |
3 |
2 |
15 |
1 |
2 |
1 |
3 |
=1
2 |
3 |
2 |
15 |
2 |
15 |
4 |
3 |
=1
2 |
3 |
2 |
15 |
4 |
3 |
=1
2 |
3 |
4 |
3 |
=1
2 |
3 |
4 |
3 |
=
1 |
3 |
⑥
2890+
| ||||||
|
=(2890+
100 |
120 |
105 |
120 |
84 |
120 |
100 |
120 |
105 |
120 |
84 |
120 |
=(2890+
289 |
120 |
120 |
289 |
=2890×
120 |
289 |
289 |
120 |
120 |
289 |
=1200+1,
=1201.
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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