题目内容
| 解方程. 7
|
80%x-
|
|
分析:(1)原式变为7.3x+2.7=4.5,根据等式的性质,两边同减去2.7,再同除以7.3即可;
(2)原式变为0.8x-0.4x=2,即0.4x=2,根据等式的性质,两边同除以0.4即可;
(3)根据等式的性质,两边同乘x,得
×x=
,两边同乘
即可.
(2)原式变为0.8x-0.4x=2,即0.4x=2,根据等式的性质,两边同除以0.4即可;
(3)根据等式的性质,两边同乘x,得
| 2 |
| 5 |
| 13 |
| 17 |
| 5 |
| 2 |
解答:解:(1)7
x+2
=4
7.3x+2.7=4.5
7.3x+2.7-2.7=4.5-2.7
7.3x=1.8
x=
(2)80%x-
x=2
0.8x-0.4x=2
0.4x=2
0.4x÷0.4=2÷0.4
x=5
(3)
÷x=
÷x×x=
×x
×x=
×x×
=
×
x=
| 3 |
| 10 |
| 7 |
| 10 |
| 1 |
| 2 |
7.3x+2.7=4.5
7.3x+2.7-2.7=4.5-2.7
7.3x=1.8
x=
| 18 |
| 73 |
(2)80%x-
| 2 |
| 5 |
0.8x-0.4x=2
0.4x=2
0.4x÷0.4=2÷0.4
x=5
(3)
| 13 |
| 17 |
| 2 |
| 5 |
| 13 |
| 17 |
| 2 |
| 5 |
| 2 |
| 5 |
| 13 |
| 17 |
| 2 |
| 5 |
| 5 |
| 2 |
| 13 |
| 17 |
| 5 |
| 2 |
x=
| 65 |
| 34 |
点评:此题考查了根据等式的性质解方程,即等式两边同加上、同减去、同乘上或同除以一个不为0的数,等式仍相等.同时注意“=”上下要对齐.
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