题目内容
递等式计算.(能简便的用简便)
|
|
1-(
|
分析:(1)运用加法交换律与结合律简算;
(2)先通分,运用加法结合律简算;
(3)先算括号内的,再算括号外的.
(2)先通分,运用加法结合律简算;
(3)先算括号内的,再算括号外的.
解答:解:(1)
+
+
=(
+
)+
=1+
=1
;
(2)
-
-
=
-
-
=
-(
+
)
=
-
=0;
(3)1-(
+
)
=1-
=
.
| 5 |
| 9 |
| 1 |
| 5 |
| 4 |
| 9 |
=(
| 5 |
| 9 |
| 4 |
| 9 |
| 1 |
| 5 |
=1+
| 1 |
| 5 |
=1
| 1 |
| 5 |
(2)
| 8 |
| 15 |
| 1 |
| 3 |
| 1 |
| 5 |
=
| 8 |
| 15 |
| 5 |
| 15 |
| 3 |
| 15 |
=
| 8 |
| 15 |
| 5 |
| 15 |
| 3 |
| 15 |
=
| 8 |
| 15 |
| 8 |
| 15 |
=0;
(3)1-(
| 1 |
| 3 |
| 5 |
| 12 |
=1-
| 3 |
| 4 |
=
| 1 |
| 4 |
点评:此题考查了分数的四则混合运算,注意运算顺序以及运用运算定律进行简算.
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