题目内容
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分析:(1)根据等式的性质,两边同乘
即可;
(2)根据等式的性质,两边同乘
即可;
(3)根据等式的性质,两边同乘x,得
x=
,两边同乘
即可;
(4)根据等式的性质,两边同乘
即可.
| 8 |
| 7 |
(2)根据等式的性质,两边同乘
| 23 |
| 9 |
(3)根据等式的性质,两边同乘x,得
| 5 |
| 18 |
| 9 |
| 23 |
| 18 |
| 5 |
(4)根据等式的性质,两边同乘
| 19 |
| 6 |
解答:解:(1)
x=
x×
=
×
x=
;
(2)
÷x=
÷x×x=
×x
x=
x×
=
×
x=
;
(3)
x=
x×
=
×
x=6;
(4)
x=
x×
=
×
x=2.
| 7 |
| 8 |
| 3 |
| 7 |
| 7 |
| 8 |
| 8 |
| 7 |
| 3 |
| 7 |
| 8 |
| 7 |
x=
| 24 |
| 49 |
(2)
| 9 |
| 23 |
| 5 |
| 18 |
| 9 |
| 23 |
| 5 |
| 18 |
| 5 |
| 18 |
| 9 |
| 23 |
| 5 |
| 18 |
| 18 |
| 5 |
| 9 |
| 23 |
| 18 |
| 5 |
x=
| 162 |
| 115 |
(3)
| 11 |
| 12 |
| 33 |
| 6 |
| 11 |
| 12 |
| 12 |
| 11 |
| 33 |
| 6 |
| 12 |
| 11 |
x=6;
(4)
| 6 |
| 19 |
| 12 |
| 19 |
| 6 |
| 19 |
| 19 |
| 6 |
| 12 |
| 19 |
| 19 |
| 6 |
x=2.
点评:此题考查了运用等式的性质解方程,即等式两边同加上或同减去、同乘上或同除以一个数(0除外),两边仍相等,同时注意“=”上下要对齐.
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